2s+2(s+2)=4(s+2)-4

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Solution for 2s+2(s+2)=4(s+2)-4 equation: 


Simplifying
2s + 2(s + 2) = 4(s + 2) + -4

Reorder the terms:
2s + 2(2 + s) = 4(s + 2) + -4
2s + (2 * 2 + s * 2) = 4(s + 2) + -4
2s + (4 + 2s) = 4(s + 2) + -4

Reorder the terms:
4 + 2s + 2s = 4(s + 2) + -4

Combine like terms: 2s + 2s = 4s
4 + 4s = 4(s + 2) + -4

Reorder the terms:
4 + 4s = 4(2 + s) + -4
4 + 4s = (2 * 4 + s * 4) + -4
4 + 4s = (8 + 4s) + -4

Reorder the terms:
4 + 4s = 8 + -4 + 4s

Combine like terms: 8 + -4 = 4
4 + 4s = 4 + 4s

Add '-4' to each side of the equation.
4 + -4 + 4s = 4 + -4 + 4s

Combine like terms: 4 + -4 = 0
0 + 4s = 4 + -4 + 4s
4s = 4 + -4 + 4s

Combine like terms: 4 + -4 = 0
4s = 0 + 4s
4s = 4s

Add '-4s' to each side of the equation.
4s + -4s = 4s + -4s

Combine like terms: 4s + -4s = 0
0 = 4s + -4s

Combine like terms: 4s + -4s = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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