2s+4=5(-4/2s)

Solution for 2s+4=5(-4/2s) equation:

2s+4=5(-4/2s)

We move all terms to the left:

2s+4-(5(-4/2s))=0


Domain of the equation: 2s))!=0

s!=0/1

s!=0

s∈R


We multiply all the terms by the denominator


2s*2s))-(5(+4*2s))-4=0

Wy multiply elements

4s^2+8s=0

a = 4; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·4·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*4}=\frac{-16}{8}
=-2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*4}=\frac{0}{8}
=0
$