2s+5=5(-4-2s)

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Solution for 2s+5=5(-4-2s) equation: 



2s+5=5(-4-2s)

We move all terms to the left:

2s+5-(5(-4-2s))=0

We add all the numbers together, and all the variables

2s-(5(-2s-4))+5=0



We calculate terms in parentheses: -(5(-2s-4)), so:

5(-2s-4)

We multiply parentheses

-10s-20

Back to the equation:

-(-10s-20)



We get rid of parentheses

2s+10s+20+5=0

We add all the numbers together, and all the variables

12s+25=0

We move all terms containing s to the left, all other terms to the right

12s=-25

s=-25/12

s=-2+1/12

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