2s-3t=42;3s+2t=24

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2x+y=8
x+3y=14

Solution for 2s-3t=42;3s+2t=24 system of equations: 


  • /| 2*s-(3*t)-42 = 0| 3*s+2*t-24 = 0
  • We try to solve the equation: 2*s-(3*t)-42 = 0
  • 2*s-3*t-42 = 0 // - 2*s-42
  • -3*t = -(2*s-42) // : -3
  • t = (-(2*s-42))/(-3)
  • t = (42-(2*s))/(-3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*((42-(2*s))/(-3))+3*s-24 = 0| t = (42-(2*s))/(-3)
  • (2*(42-2*s))/(-3)+3*s-24 = 0
  • 13/3*s-28-24 = 0
  • 13/3*s-52 = 0
  • 13/3*s-52 = 0 // + 52
  • 13/3*s = 52 // : 13/3
  • s = 52/13/3
  • s = 12
  • We insert the solution into one of the initial equations of our system of equations
  • For t = (42-(2*s))/(-3): 
  • t = (42-(2*12))/(-3)
  • t = (42-24)/(-3)
  • t = 18/(-3)
  • t = -6
  • We get a system of equations:
  • /| t = -6| s = 12

 

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