2s1/3x+4d-1=4/3x-3+x

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Solution for 2s1/3x+4d-1=4/3x-3+x equation: 


x in (-oo:+oo)

4*d+((2*s^1)/3)*x-1 = (4/3)*x+x-3 // - (4/3)*x+x-3

4*d+((2*s^1)/3)*x-((4/3)*x)-x-1+3 = 0

4*d+((2*s)/3)*x+(-4/3)*x-x-1+3 = 0

4*d-7/3*x+2 = 0 // - 4*d+2

-7/3*x = -(4*d+2) // : -7/3

x = (-(4*d+2))/(-7/3)

x = 3/7*(4*d+2)

x = 3/7*(4*d+2)

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