2sin(2x)+5cos(2x)=0

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Solution for 2sin(2x)+5cos(2x)=0 equation:


Simplifying
2sin(2x) + 5cos(2x) = 0

Remove parenthesis around (2x)
2ins * 2x + 5cos(2x) = 0

Reorder the terms for easier multiplication:
2 * 2ins * x + 5cos(2x) = 0

Multiply 2 * 2
4ins * x + 5cos(2x) = 0

Multiply ins * x
4insx + 5cos(2x) = 0

Remove parenthesis around (2x)
4insx + 5cos * 2x = 0

Reorder the terms for easier multiplication:
4insx + 5 * 2cos * x = 0

Multiply 5 * 2
4insx + 10cos * x = 0

Multiply cos * x
4insx + 10cosx = 0

Reorder the terms:
10cosx + 4insx = 0

Solving
10cosx + 4insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4insx' to each side of the equation.
10cosx + 4insx + -4insx = 0 + -4insx

Combine like terms: 4insx + -4insx = 0
10cosx + 0 = 0 + -4insx
10cosx = 0 + -4insx
Remove the zero:
10cosx = -4insx

Divide each side by '10osx'.
c = -0.4ino-1

Simplifying
c = -0.4ino-1

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