2sin(2x)cosx+2cos(2x)sinx=1

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Solution for 2sin(2x)cosx+2cos(2x)sinx=1 equation:


Simplifying
2sin(2x) * cosx + 2cos(2x) * sinx = 1

Remove parenthesis around (2x)
2ins * 2x * cosx + 2cos(2x) * sinx = 1

Reorder the terms for easier multiplication:
2 * 2ins * x * cosx + 2cos(2x) * sinx = 1

Multiply 2 * 2
4ins * x * cosx + 2cos(2x) * sinx = 1

Multiply ins * x
4insx * cosx + 2cos(2x) * sinx = 1

Multiply insx * cosx
4cinos2x2 + 2cos(2x) * sinx = 1

Remove parenthesis around (2x)
4cinos2x2 + 2cos * 2x * sinx = 1

Reorder the terms for easier multiplication:
4cinos2x2 + 2 * 2cos * x * insx = 1

Multiply 2 * 2
4cinos2x2 + 4cos * x * insx = 1

Multiply cos * x
4cinos2x2 + 4cosx * insx = 1

Multiply cosx * insx
4cinos2x2 + 4cinos2x2 = 1

Combine like terms: 4cinos2x2 + 4cinos2x2 = 8cinos2x2
8cinos2x2 = 1

Solving
8cinos2x2 = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '8inos2x2'.
c = 0.125i-1n-1o-1s-2x-2

Simplifying
c = 0.125i-1n-1o-1s-2x-2

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