2sin(x)+7cos(x)+2=0

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Solution for 2sin(x)+7cos(x)+2=0 equation:


Simplifying
2sin(x) + 7cos(x) + 2 = 0

Multiply ins * x
2insx + 7cos(x) + 2 = 0

Multiply cos * x
2insx + 7cosx + 2 = 0

Reorder the terms:
2 + 7cosx + 2insx = 0

Solving
2 + 7cosx + 2insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 7cosx + -2 + 2insx = 0 + -2

Reorder the terms:
2 + -2 + 7cosx + 2insx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 7cosx + 2insx = 0 + -2
7cosx + 2insx = 0 + -2

Combine like terms: 0 + -2 = -2
7cosx + 2insx = -2

Add '-2insx' to each side of the equation.
7cosx + 2insx + -2insx = -2 + -2insx

Combine like terms: 2insx + -2insx = 0
7cosx + 0 = -2 + -2insx
7cosx = -2 + -2insx

Divide each side by '7osx'.
c = -0.2857142857o-1s-1x-1 + -0.2857142857ino-1

Simplifying
c = -0.2857142857o-1s-1x-1 + -0.2857142857ino-1

Reorder the terms:
c = -0.2857142857ino-1 + -0.2857142857o-1s-1x-1

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