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2t(t+2)=-6
We move all terms to the left:
2t(t+2)-(-6)=0
We add all the numbers together, and all the variables
2t(t+2)+6=0
We multiply parentheses
2t^2+4t+6=0
a = 2; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·2·6
Δ = -32
Delta is less than zero, so there is no solution for the equation
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