2t+1+5(t-3)=3(t+1)+t

Solution for 2t+1+5(t-3)=3(t+1)+t equation:

2t+1+5(t-3)=3(t+1)+t

We move all terms to the left:

2t+1+5(t-3)-(3(t+1)+t)=0

We multiply parentheses

2t+5t-(3(t+1)+t)-15+1=0


We calculate terms in parentheses: -(3(t+1)+t), so:

3(t+1)+t

We add all the numbers together, and all the variables

t+3(t+1)

We multiply parentheses

t+3t+3

We add all the numbers together, and all the variables

4t+3

Back to the equation:

-(4t+3)


We add all the numbers together, and all the variables

7t-(4t+3)-14=0

We get rid of parentheses

7t-4t-3-14=0

We add all the numbers together, and all the variables

3t-17=0

We move all terms containing t to the left, all other terms to the right

3t=17

t=17/3

t=5+2/3