2t+1/t-1=6t+1/3t-1

Solution for 2t+1/t-1=6t+1/3t-1 equation:

2t+1/t-1=6t+1/3t-1

We move all terms to the left:

2t+1/t-1-(6t+1/3t-1)=0


Domain of the equation: t!=0

t∈R



Domain of the equation: 3t-1)!=0

t∈R


We get rid of parentheses

2t+1/t-6t-1/3t+1-1=0

We calculate fractions


2t-6t+3t/3t^2+(-t)/3t^2+1-1=0

We add all the numbers together, and all the variables

2t-6t+3t/3t^2+(-1t)/3t^2+1-1=0

We add all the numbers together, and all the variables

-4t+3t/3t^2+(-1t)/3t^2=0

We multiply all the terms by the denominator


-4t*3t^2+3t+(-1t)=0

We add all the numbers together, and all the variables

3t-4t*3t^2+(-1t)=0

Wy multiply elements

-12t^3+3t+(-1t)=0

We get rid of parentheses

-12t^3+3t-1t=0

We do not support etpression: t^3