2t+3(2t-1)=t+4(t-2)

Solution for 2t+3(2t-1)=t+4(t-2) equation:

2t+3(2t-1)=t+4(t-2)

We move all terms to the left:

2t+3(2t-1)-(t+4(t-2))=0

We multiply parentheses

2t+6t-(t+4(t-2))-3=0


We calculate terms in parentheses: -(t+4(t-2)), so:

t+4(t-2)

We multiply parentheses

t+4t-8

We add all the numbers together, and all the variables

5t-8

Back to the equation:

-(5t-8)


We add all the numbers together, and all the variables

8t-(5t-8)-3=0

We get rid of parentheses

8t-5t+8-3=0

We add all the numbers together, and all the variables

3t+5=0

We move all terms containing t to the left, all other terms to the right

3t=-5

t=-5/3

t=-1+2/3