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2t+3(t-4)=6-2(3t-2)
We move all terms to the left:
2t+3(t-4)-(6-2(3t-2))=0
We multiply parentheses
2t+3t-(6-2(3t-2))-12=0
We calculate terms in parentheses: -(6-2(3t-2)), so:We add all the numbers together, and all the variables
6-2(3t-2)
determiningTheFunctionDomain -2(3t-2)+6
We multiply parentheses
-6t+4+6
We add all the numbers together, and all the variables
-6t+10
Back to the equation:
-(-6t+10)
5t-(-6t+10)-12=0
We get rid of parentheses
5t+6t-10-12=0
We add all the numbers together, and all the variables
11t-22=0
We move all terms containing t to the left, all other terms to the right
11t=22
t=22/11
t=2
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