2t+3(t-4)=6-2(6t-2)

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Solution for 2t+3(t-4)=6-2(6t-2) equation: 



2t+3(t-4)=6-2(6t-2)

We move all terms to the left:

2t+3(t-4)-(6-2(6t-2))=0

We multiply parentheses

2t+3t-(6-2(6t-2))-12=0



We calculate terms in parentheses: -(6-2(6t-2)), so:

6-2(6t-2)

determiningTheFunctionDomain
-2(6t-2)+6

We multiply parentheses

-12t+4+6

We add all the numbers together, and all the variables

-12t+10

Back to the equation:

-(-12t+10)



We add all the numbers together, and all the variables

5t-(-12t+10)-12=0

We get rid of parentheses

5t+12t-10-12=0

We add all the numbers together, and all the variables

17t-22=0

We move all terms containing t to the left, all other terms to the right

17t=22

t=22/17

t=1+5/17

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