2t+4(t-1)=5(t-1)

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Solution for 2t+4(t-1)=5(t-1) equation: 



2t+4(t-1)=5(t-1)

We move all terms to the left:

2t+4(t-1)-(5(t-1))=0

We multiply parentheses

2t+4t-(5(t-1))-4=0



We calculate terms in parentheses: -(5(t-1)), so:

5(t-1)

We multiply parentheses

5t-5

Back to the equation:

-(5t-5)



We add all the numbers together, and all the variables

6t-(5t-5)-4=0

We get rid of parentheses

6t-5t+5-4=0

We add all the numbers together, and all the variables

t+1=0

We move all terms containing t to the left, all other terms to the right

t=-1

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