2t+4=13t+6(t-5)

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Solution for 2t+4=13t+6(t-5) equation: 



2t+4=13t+6(t-5)

We move all terms to the left:

2t+4-(13t+6(t-5))=0



We calculate terms in parentheses: -(13t+6(t-5)), so:

13t+6(t-5)

We multiply parentheses

13t+6t-30

We add all the numbers together, and all the variables

19t-30

Back to the equation:

-(19t-30)



We get rid of parentheses

2t-19t+30+4=0

We add all the numbers together, and all the variables

-17t+34=0

We move all terms containing t to the left, all other terms to the right

-17t=-34

t=-34/-17

t=+2

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