2t+4=3(t-2)

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Solution for 2t+4=3(t-2) equation: 



2t+4=3(t-2)

We move all terms to the left:

2t+4-(3(t-2))=0



We calculate terms in parentheses: -(3(t-2)), so:

3(t-2)

We multiply parentheses

3t-6

Back to the equation:

-(3t-6)



We get rid of parentheses

2t-3t+6+4=0

We add all the numbers together, and all the variables

-1t+10=0

We move all terms containing t to the left, all other terms to the right

-t=-10

t=-10/-1

t=+10

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