2t+7/(2t-1)(3t+4)

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Solution for 2t+7/(2t-1)(3t+4) equation: 


D( t )

2*t-1 = 0

2*t-1 = 0

2*t-1 = 0

2*t-1 = 0 // + 1

2*t = 1 // : 2

t = 1/2

t in (-oo:1/2) U (1/2:+oo)

(7/(2*t-1))*(3*t+4)+2*t = 0

(7*(3*t+4))/(2*t-1)+2*t = 0

(7*(3*t+4))/(2*t-1)+(2*t*(2*t-1))/(2*t-1) = 0

7*(3*t+4)+2*t*(2*t-1) = 0

4*t^2+19*t+28 = 0

4*t^2+19*t+28 = 0

4*t^2+19*t+28 = 0

DELTA = 19^2-(4*4*28)

DELTA = -87

DELTA < 0

1 = 0

1/(2*t-1) = 0

1/(2*t-1) = 0 // * 2*t-1

1 = 0

t belongs to the empty set

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