2t-2(3t+8)=-4(2-t)

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Solution for 2t-2(3t+8)=-4(2-t) equation: 



2t-2(3t+8)=-4(2-t)

We move all terms to the left:

2t-2(3t+8)-(-4(2-t))=0

We add all the numbers together, and all the variables

2t-2(3t+8)-(-4(-1t+2))=0

We multiply parentheses

2t-6t-(-4(-1t+2))-16=0



We calculate terms in parentheses: -(-4(-1t+2)), so:

-4(-1t+2)

We multiply parentheses

4t-8

Back to the equation:

-(4t-8)



We add all the numbers together, and all the variables

-4t-(4t-8)-16=0

We get rid of parentheses

-4t-4t+8-16=0

We add all the numbers together, and all the variables

-8t-8=0

We move all terms containing t to the left, all other terms to the right

-8t=8

t=8/-8

t=-1

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