2t-6(2t-2)t+3))+5=8+5t-4t

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Solution for 2t-6(2t-2)t+3))+5=8+5t-4t equation:



2t-6(2t-2)t+3))+5=8+5t-4t
We move all terms to the left:
2t-6(2t-2)t+3))+5-(8+5t-4t)=0
We add all the numbers together, and all the variables
2t-6(2t-2)t+3))+5-(t+8)=0
We multiply parentheses
-12t^2+2t+12t+3))+5-(t+8)=0
We add all the numbers together, and all the variables
-12t^2+14t+3))+5-(t+8)=0

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