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2t^2+2=t
We move all terms to the left:
2t^2+2-(t)=0
We add all the numbers together, and all the variables
2t^2-1t+2=0
a = 2; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·2·2
Δ = -15
Delta is less than zero, so there is no solution for the equation
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