2t2+8t+8=0

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Solution for 2t2+8t+8=0 equation: 



2t^2+8t+8=0

a = 2; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-8}{4}=-2$

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