2t2-50t-25000=0

Solution for 2t2-50t-25000=0 equation:

2t^2-50t-25000=0

a = 2; b = -50; c = -25000;
Δ = b2-4ac
Δ = -502-4·2·(-25000)
Δ = 202500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{202500}=450$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-450}{2*2}=\frac{-400}{4}
=-100
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+450}{2*2}=\frac{500}{4}
=125
$