2t2=121/196

Solution for 2t2=121/196 equation:

2t^2=121/196

We move all terms to the left:

2t^2-(121/196)=0

We add all the numbers together, and all the variables

2t^2-(+121/196)=0

We get rid of parentheses

2t^2-121/196=0

We multiply all the terms by the denominator


2t^2*196-121=0

Wy multiply elements

392t^2-121=0

a = 392; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·392·(-121)
Δ = 189728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{189728}=\sqrt{94864*2}=\sqrt{94864}*\sqrt{2}=308\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-308\sqrt{2}}{2*392}=\frac{0-308\sqrt{2}}{784}
=-\frac{308\sqrt{2}}{784}
=-\frac{11\sqrt{2}}{28}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+308\sqrt{2}}{2*392}=\frac{0+308\sqrt{2}}{784}
=\frac{308\sqrt{2}}{784}
=\frac{11\sqrt{2}}{28}
$