2t2=25t

Solution for 2t2=25t equation:

2t^2=25t

We move all terms to the left:

2t^2-(25t)=0

a = 2; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·2·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*2}=\frac{0}{4}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*2}=\frac{50}{4}
=12+1/2
$