2t2=26,5t

Solution for 2t2=26,5t equation:

2t^2=26.5t

We move all terms to the left:

2t^2-(26.5t)=0

We add all the numbers together, and all the variables

2t^2-(+26.5t)=0

We get rid of parentheses

2t^2-26.5t=0

a = 2; b = -26.5; c = 0;
Δ = b2-4ac
Δ = -26.52-4·2·0
Δ = 702.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26.5)-\sqrt{702.25}}{2*2}=\frac{26.5-\sqrt{702.25}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26.5)+\sqrt{702.25}}{2*2}=\frac{26.5+\sqrt{702.25}}{4}
$