2t2=5312t

Solution for 2t2=5312t equation:

2t^2=5312t

We move all terms to the left:

2t^2-(5312t)=0

a = 2; b = -5312; c = 0;
Δ = b2-4ac
Δ = -53122-4·2·0
Δ = 28217344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28217344}=5312$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5312)-5312}{2*2}=\frac{0}{4}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5312)+5312}{2*2}=\frac{10624}{4}
=2656
$