2t2=70

Solution for 2t2=70 equation:

2t^2=70

We move all terms to the left:

2t^2-(70)=0

a = 2; b = 0; c = -70;
Δ = b2-4ac
Δ = 02-4·2·(-70)
Δ = 560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{560}=\sqrt{16*35}=\sqrt{16}*\sqrt{35}=4\sqrt{35}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{35}}{2*2}=\frac{0-4\sqrt{35}}{4}
=-\frac{4\sqrt{35}}{4}
=-\sqrt{35}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{35}}{2*2}=\frac{0+4\sqrt{35}}{4}
=\frac{4\sqrt{35}}{4}
=\sqrt{35}
$