2t=3(t-1)+4

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Solution for 2t=3(t-1)+4 equation: 



2t=3(t-1)+4

We move all terms to the left:

2t-(3(t-1)+4)=0



We calculate terms in parentheses: -(3(t-1)+4), so:

3(t-1)+4

We multiply parentheses

3t-3+4

We add all the numbers together, and all the variables

3t+1

Back to the equation:

-(3t+1)



We get rid of parentheses

2t-3t-1=0

We add all the numbers together, and all the variables

-1t-1=0

We move all terms containing t to the left, all other terms to the right

-t=1

t=1/-1

t=-1

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