2t=3(t-1)+5

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Solution for 2t=3(t-1)+5 equation: 



2t=3(t-1)+5

We move all terms to the left:

2t-(3(t-1)+5)=0



We calculate terms in parentheses: -(3(t-1)+5), so:

3(t-1)+5

We multiply parentheses

3t-3+5

We add all the numbers together, and all the variables

3t+2

Back to the equation:

-(3t+2)



We get rid of parentheses

2t-3t-2=0

We add all the numbers together, and all the variables

-1t-2=0

We move all terms containing t to the left, all other terms to the right

-t=2

t=2/-1

t=-2

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