2t=6/t-4

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Solution for 2t=6/t-4 equation:



2t=6/t-4
We move all terms to the left:
2t-(6/t-4)=0
Domain of the equation: t-4)!=0
t∈R
We get rid of parentheses
2t-6/t+4=0
We multiply all the terms by the denominator
2t*t+4*t-6=0
We add all the numbers together, and all the variables
4t+2t*t-6=0
Wy multiply elements
2t^2+4t-6=0
a = 2; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·2·(-6)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*2}=\frac{-12}{4} =-3 $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*2}=\frac{4}{4} =1 $

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