2u(3u+4)+3u(2u+1)=

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Solution for 2u(3u+4)+3u(2u+1)= equation:


Simplifying
2u(3u + 4) + 3u(2u + 1) = 0

Reorder the terms:
2u(4 + 3u) + 3u(2u + 1) = 0
(4 * 2u + 3u * 2u) + 3u(2u + 1) = 0
(8u + 6u2) + 3u(2u + 1) = 0

Reorder the terms:
8u + 6u2 + 3u(1 + 2u) = 0
8u + 6u2 + (1 * 3u + 2u * 3u) = 0
8u + 6u2 + (3u + 6u2) = 0

Reorder the terms:
8u + 3u + 6u2 + 6u2 = 0

Combine like terms: 8u + 3u = 11u
11u + 6u2 + 6u2 = 0

Combine like terms: 6u2 + 6u2 = 12u2
11u + 12u2 = 0

Solving
11u + 12u2 = 0

Solving for variable 'u'.

Factor out the Greatest Common Factor (GCF), 'u'.
u(11 + 12u) = 0

Subproblem 1

Set the factor 'u' equal to zero and attempt to solve: Simplifying u = 0 Solving u = 0 Move all terms containing u to the left, all other terms to the right. Simplifying u = 0

Subproblem 2

Set the factor '(11 + 12u)' equal to zero and attempt to solve: Simplifying 11 + 12u = 0 Solving 11 + 12u = 0 Move all terms containing u to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + 12u = 0 + -11 Combine like terms: 11 + -11 = 0 0 + 12u = 0 + -11 12u = 0 + -11 Combine like terms: 0 + -11 = -11 12u = -11 Divide each side by '12'. u = -0.9166666667 Simplifying u = -0.9166666667

Solution

u = {0, -0.9166666667}

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