2u+22=4(u+1)

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Solution for 2u+22=4(u+1) equation: 



2u+22=4(u+1)

We move all terms to the left:

2u+22-(4(u+1))=0



We calculate terms in parentheses: -(4(u+1)), so:

4(u+1)

We multiply parentheses

4u+4

Back to the equation:

-(4u+4)



We get rid of parentheses

2u-4u-4+22=0

We add all the numbers together, and all the variables

-2u+18=0

We move all terms containing u to the left, all other terms to the right

-2u=-18

u=-18/-2

u=+9

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