2u+22=6(u+1)

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Solution for 2u+22=6(u+1) equation: 



2u+22=6(u+1)

We move all terms to the left:

2u+22-(6(u+1))=0



We calculate terms in parentheses: -(6(u+1)), so:

6(u+1)

We multiply parentheses

6u+6

Back to the equation:

-(6u+6)



We get rid of parentheses

2u-6u-6+22=0

We add all the numbers together, and all the variables

-4u+16=0

We move all terms containing u to the left, all other terms to the right

-4u=-16

u=-16/-4

u=+4

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