2u+2=4(4-u)

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Solution for 2u+2=4(4-u) equation: 



2u+2=4(4-u)

We move all terms to the left:

2u+2-(4(4-u))=0

We add all the numbers together, and all the variables

2u-(4(-1u+4))+2=0



We calculate terms in parentheses: -(4(-1u+4)), so:

4(-1u+4)

We multiply parentheses

-4u+16

Back to the equation:

-(-4u+16)



We get rid of parentheses

2u+4u-16+2=0

We add all the numbers together, and all the variables

6u-14=0

We move all terms containing u to the left, all other terms to the right

6u=14

u=14/6

u=2+1/3

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