2u+3-3(-4u-3)=2(u-3)

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Solution for 2u+3-3(-4u-3)=2(u-3) equation: 



2u+3-3(-4u-3)=2(u-3)

We move all terms to the left:

2u+3-3(-4u-3)-(2(u-3))=0

We multiply parentheses

2u+12u-(2(u-3))+9+3=0



We calculate terms in parentheses: -(2(u-3)), so:

2(u-3)

We multiply parentheses

2u-6

Back to the equation:

-(2u-6)



We add all the numbers together, and all the variables

14u-(2u-6)+12=0

We get rid of parentheses

14u-2u+6+12=0

We add all the numbers together, and all the variables

12u+18=0

We move all terms containing u to the left, all other terms to the right

12u=-18

u=-18/12

u=-1+1/2

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