2u+4-2(-4u-2)=2(u-1)

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Solution for 2u+4-2(-4u-2)=2(u-1) equation: 



2u+4-2(-4u-2)=2(u-1)

We move all terms to the left:

2u+4-2(-4u-2)-(2(u-1))=0

We multiply parentheses

2u+8u-(2(u-1))+4+4=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We add all the numbers together, and all the variables

10u-(2u-2)+8=0

We get rid of parentheses

10u-2u+2+8=0

We add all the numbers together, and all the variables

8u+10=0

We move all terms containing u to the left, all other terms to the right

8u=-10

u=-10/8

u=-1+1/4

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