2u+4=3u+3(u-2)-4

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Solution for 2u+4=3u+3(u-2)-4 equation: 



2u+4=3u+3(u-2)-4

We move all terms to the left:

2u+4-(3u+3(u-2)-4)=0



We calculate terms in parentheses: -(3u+3(u-2)-4), so:

3u+3(u-2)-4

We multiply parentheses

3u+3u-6-4

We add all the numbers together, and all the variables

6u-10

Back to the equation:

-(6u-10)



We get rid of parentheses

2u-6u+10+4=0

We add all the numbers together, and all the variables

-4u+14=0

We move all terms containing u to the left, all other terms to the right

-4u=-14

u=-14/-4

u=3+1/2

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