2u-1+2(5u+2)=-4(u+2)

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Solution for 2u-1+2(5u+2)=-4(u+2) equation: 



2u-1+2(5u+2)=-4(u+2)

We move all terms to the left:

2u-1+2(5u+2)-(-4(u+2))=0

We multiply parentheses

2u+10u-(-4(u+2))+4-1=0



We calculate terms in parentheses: -(-4(u+2)), so:

-4(u+2)

We multiply parentheses

-4u-8

Back to the equation:

-(-4u-8)



We add all the numbers together, and all the variables

12u-(-4u-8)+3=0

We get rid of parentheses

12u+4u+8+3=0

We add all the numbers together, and all the variables

16u+11=0

We move all terms containing u to the left, all other terms to the right

16u=-11

u=-11/16

u=-11/16

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