2u-2(10+7u)=10-(8u+6)

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Solution for 2u-2(10+7u)=10-(8u+6) equation: 



2u-2(10+7u)=10-(8u+6)

We move all terms to the left:

2u-2(10+7u)-(10-(8u+6))=0

We add all the numbers together, and all the variables

2u-2(7u+10)-(10-(8u+6))=0

We multiply parentheses

2u-14u-(10-(8u+6))-20=0



We calculate terms in parentheses: -(10-(8u+6)), so:

10-(8u+6)

determiningTheFunctionDomain
-(8u+6)+10

We get rid of parentheses

-8u-6+10

We add all the numbers together, and all the variables

-8u+4

Back to the equation:

-(-8u+4)



We add all the numbers together, and all the variables

-12u-(-8u+4)-20=0

We get rid of parentheses

-12u+8u-4-20=0

We add all the numbers together, and all the variables

-4u-24=0

We move all terms containing u to the left, all other terms to the right

-4u=24

u=24/-4

u=-6

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