2u-2+2(3u+2)=-2(u+2)

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Solution for 2u-2+2(3u+2)=-2(u+2) equation:



2u-2+2(3u+2)=-2(u+2)
We move all terms to the left:
2u-2+2(3u+2)-(-2(u+2))=0
We multiply parentheses
2u+6u-(-2(u+2))+4-2=0
We calculate terms in parentheses: -(-2(u+2)), so:
-2(u+2)
We multiply parentheses
-2u-4
Back to the equation:
-(-2u-4)
We add all the numbers together, and all the variables
8u-(-2u-4)+2=0
We get rid of parentheses
8u+2u+4+2=0
We add all the numbers together, and all the variables
10u+6=0
We move all terms containing u to the left, all other terms to the right
10u=-6
u=-6/10
u=-3/5

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