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2u-3+2(3u+2)=-2(u+2)
We move all terms to the left:
2u-3+2(3u+2)-(-2(u+2))=0
We multiply parentheses
2u+6u-(-2(u+2))+4-3=0
We calculate terms in parentheses: -(-2(u+2)), so:We add all the numbers together, and all the variables
-2(u+2)
We multiply parentheses
-2u-4
Back to the equation:
-(-2u-4)
8u-(-2u-4)+1=0
We get rid of parentheses
8u+2u+4+1=0
We add all the numbers together, and all the variables
10u+5=0
We move all terms containing u to the left, all other terms to the right
10u=-5
u=-5/10
u=-1/2
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