2u-3+3(3u+2)=-3(u+3)

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Solution for 2u-3+3(3u+2)=-3(u+3) equation: 



2u-3+3(3u+2)=-3(u+3)

We move all terms to the left:

2u-3+3(3u+2)-(-3(u+3))=0

We multiply parentheses

2u+9u-(-3(u+3))+6-3=0



We calculate terms in parentheses: -(-3(u+3)), so:

-3(u+3)

We multiply parentheses

-3u-9

Back to the equation:

-(-3u-9)



We add all the numbers together, and all the variables

11u-(-3u-9)+3=0

We get rid of parentheses

11u+3u+9+3=0

We add all the numbers together, and all the variables

14u+12=0

We move all terms containing u to the left, all other terms to the right

14u=-12

u=-12/14

u=-6/7

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