2u-4+2(4u+5)=-6(u+2)

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Solution for 2u-4+2(4u+5)=-6(u+2) equation: 



2u-4+2(4u+5)=-6(u+2)

We move all terms to the left:

2u-4+2(4u+5)-(-6(u+2))=0

We multiply parentheses

2u+8u-(-6(u+2))+10-4=0



We calculate terms in parentheses: -(-6(u+2)), so:

-6(u+2)

We multiply parentheses

-6u-12

Back to the equation:

-(-6u-12)



We add all the numbers together, and all the variables

10u-(-6u-12)+6=0

We get rid of parentheses

10u+6u+12+6=0

We add all the numbers together, and all the variables

16u+18=0

We move all terms containing u to the left, all other terms to the right

16u=-18

u=-18/16

u=-1+1/8

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