2u-4=4(4-u)-2

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Solution for 2u-4=4(4-u)-2 equation: 



2u-4=4(4-u)-2

We move all terms to the left:

2u-4-(4(4-u)-2)=0

We add all the numbers together, and all the variables

2u-(4(-1u+4)-2)-4=0



We calculate terms in parentheses: -(4(-1u+4)-2), so:

4(-1u+4)-2

We multiply parentheses

-4u+16-2

We add all the numbers together, and all the variables

-4u+14

Back to the equation:

-(-4u+14)



We get rid of parentheses

2u+4u-14-4=0

We add all the numbers together, and all the variables

6u-18=0

We move all terms containing u to the left, all other terms to the right

6u=18

u=18/6

u=3

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