2u-6+3(2u+4)=-6(u+1)

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Solution for 2u-6+3(2u+4)=-6(u+1) equation: 



2u-6+3(2u+4)=-6(u+1)

We move all terms to the left:

2u-6+3(2u+4)-(-6(u+1))=0

We multiply parentheses

2u+6u-(-6(u+1))+12-6=0



We calculate terms in parentheses: -(-6(u+1)), so:

-6(u+1)

We multiply parentheses

-6u-6

Back to the equation:

-(-6u-6)



We add all the numbers together, and all the variables

8u-(-6u-6)+6=0

We get rid of parentheses

8u+6u+6+6=0

We add all the numbers together, and all the variables

14u+12=0

We move all terms containing u to the left, all other terms to the right

14u=-12

u=-12/14

u=-6/7

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