2u-8+2(4u+1)=-4(u+4)

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Solution for 2u-8+2(4u+1)=-4(u+4) equation: 



2u-8+2(4u+1)=-4(u+4)

We move all terms to the left:

2u-8+2(4u+1)-(-4(u+4))=0

We multiply parentheses

2u+8u-(-4(u+4))+2-8=0



We calculate terms in parentheses: -(-4(u+4)), so:

-4(u+4)

We multiply parentheses

-4u-16

Back to the equation:

-(-4u-16)



We add all the numbers together, and all the variables

10u-(-4u-16)-6=0

We get rid of parentheses

10u+4u+16-6=0

We add all the numbers together, and all the variables

14u+10=0

We move all terms containing u to the left, all other terms to the right

14u=-10

u=-10/14

u=-5/7

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