2u-8+2(6u+1)=-4(u+1)

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Solution for 2u-8+2(6u+1)=-4(u+1) equation: 



2u-8+2(6u+1)=-4(u+1)

We move all terms to the left:

2u-8+2(6u+1)-(-4(u+1))=0

We multiply parentheses

2u+12u-(-4(u+1))+2-8=0



We calculate terms in parentheses: -(-4(u+1)), so:

-4(u+1)

We multiply parentheses

-4u-4

Back to the equation:

-(-4u-4)



We add all the numbers together, and all the variables

14u-(-4u-4)-6=0

We get rid of parentheses

14u+4u+4-6=0

We add all the numbers together, and all the variables

18u-2=0

We move all terms containing u to the left, all other terms to the right

18u=2

u=2/18

u=1/9

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