2u/7+41=22

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Solution for 2u/7+41=22 equation: 



2u/7+41=22

We move all terms to the left:

2u/7+41-(22)=0

We add all the numbers together, and all the variables

2u/7+19=0

We multiply all the terms by the denominator


2u+19*7=0

We add all the numbers together, and all the variables

2u+133=0

We move all terms containing u to the left, all other terms to the right

2u=-133

u=-133/2

u=-66+1/2

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