2u/7+41=22

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Solution for 2u/7+41=22 equation:



2u/7+41=22
We move all terms to the left:
2u/7+41-(22)=0
We add all the numbers together, and all the variables
2u/7+19=0
We multiply all the terms by the denominator
2u+19*7=0
We add all the numbers together, and all the variables
2u+133=0
We move all terms containing u to the left, all other terms to the right
2u=-133
u=-133/2
u=-66+1/2

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