2u2-11u+18=(u-4)2

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Solution for 2u2-11u+18=(u-4)2 equation: 



2u^2-11u+18=(u-4)2

We move all terms to the left:

2u^2-11u+18-((u-4)2)=0



We calculate terms in parentheses: -((u-4)2), so:

(u-4)2

We multiply parentheses

2u-8

Back to the equation:

-(2u-8)



We get rid of parentheses

2u^2-11u-2u+8+18=0

We add all the numbers together, and all the variables

2u^2-13u+26=0

a = 2; b = -13; c = +26;
Δ = b2-4ac
Δ = -132-4·2·26
Δ = -39
Delta is less than zero, so there is no solution for the equation

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